MIDTERM EXAM: DISCUSSION EXAMPLES
C++ FUNDAMENTALS (Given code segments)
- Are these syntactically OK (will compile)?
- int it = 100;
- const int BIG;
- const int BIGGER = 10;
- const int BIGGEST = it;
- it = BIGGER;
- BIGGER = it;
- What gets printed?
- int i = 3, j = 3, k;
- 1 + 1 % 4 + 4 / 5
- k = ++i + ++j + 2 ;
- i = j = 3;
- k = i++ + j++ + 2 ;
- k = 6;
- k %= 5 - 1 ;
- LOOPS
Write a for loop to print the same output as while loop below.
a) Write a do loop to print the same output as while loop below.
b) What gets printed if it was "while ( i = 5 )" instead ?
- int i = 1;
- while ( i < 5 )
- {
- ++i;
- cout << i << endl;
- }
- What gets printed?
- int i, j;
- for ( i = 0; i < 2; ++i )
- for ( j = 0; j < 5; ++j )
- cout << i << " " << j << endl;
- DECISIONS
- What gets printed?
- cout << ( !3 + 2 > 1 || 0 ) << endl;
- cout << ( !3 + 2 > 1 && 0 ) << endl;
- Write an if else to print same output as switch statement below.
- int i = 3, sum = 0 ;
- switch ( i )
- {
- case 1:
- case 2:
- sum++;
- break;
- case 3:
- sum--;
- default:
- cout << i << endl;
- break;
- }
- FUNCTIONS
- What is missing?
- a) What gets printed now?
- b) Is "i" in fn() same as in main()?
- c) Write fn() to be an inline function.
- d) Write fn() to be assigned a default initializer of 1.
- e) Write fn() to be an overloaded function accepting a formal parameter type float.
- f) What makes an overloaded function?
- #include
- int main(void)
- {
- int i = 1;
- i = fn (i );
- cout << i << endl;
- cout << fn(i) << endl;
- }
- int fn ( int i ) { return(i + 2); }
- Are these legal?
- int fn (int i = 0, int j, int k = 2);
- fn (1, 2, int k = 3);
- REFERENCE TYPES
- What gets printed?
- int i = 3, &r = i;
- ++i;
- cout << i << " " << r << endl;
- What gets printed?
- #include
- void fn ( int & r );
- int main(void)
- {
- int i = 1;
- fn (i);
- cout << i << endl;
- return 0;
- }
- void fn ( int & r ) { r = 2; }
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