Truth Table for Half Adder A B S Co 0 0 0 0 0 1 1 0 1 0 1 0 1 1 0 1The logic turns out to be: S = A xor B; Co = AB




A |
B |
Ci |
S |
Co |
|---|---|---|---|---|
0 |
0 |
0 |
0 |
0 |
0 |
0 |
1 |
1 |
0 |
0 |
1 |
0 |
1 |
0 |
0 |
1 |
1 |
0 |
1 |
1 |
0 |
0 |
1 |
0 |
1 |
0 |
1 |
0 |
1 |
1 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
1 |






If you have any questions or get stuck in this tutorial, please email Chris at croedel@cs