Q1: For 123, "three" gets printed, how do I print the rest after figuring the 
    counter for the number of loops ?
Q2: How do you reverse the order so it reads the number from left to right?
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Q1: For 123, "three" gets printed, how do I print the rest after figuring the 
    counter for the number of loops ?

A1: Since you have the last digit 3 in the loop, keep going in that loop
    INCLUDING the switch/if else to print the digit "three".  Group the 
    switch/if else in the loop that extracts each digit.
    Now the next loop through will give you 2  -- print "two". ...
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Q2: How do you reverse the order so it reads the number from left to right?

A2: This has something to do with "count", the number of iterations for
    the loop to divide 123 by ten.

For 123, count is 3.
How do you get the "1" ?  Oh divide by 100 (10*10 --> 10 to the 2 power)
How do you get the "2" ?  Oh divide by 10  (10    --> 10 to the 1 power)
How do you get the "3" ?  Oh divide by 1   (1     --> 10 to the 0 power)
Notice the pattern, how many times you must divide by 10. 

For 1234, count is 4.
How do you get the "1" ?  Oh divide by 1000 (10*10*10 --> 10 to the 3 power)
How do you get the "2" ?  Oh divide by 100  (10*10    --> 10 to the 2 power)
How do you get the "3" ?  Oh divide by 10   (10       --> 10 to the 1 power)
How do you get the "4" ?  Oh divide by 1    (1        --> 10 to the 0 power)
Think on this, hint another loop.
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Q1: For 123, "three" gets printed, how do I print the rest after figuring the 
    counter for the number of loops ?
Q2: How do you reverse the order so it reads the number from left to right?
-------------------------------------------------------------------------------

Q1: For 123, "three" gets printed, how do I print the rest after figuring the 
    counter for the number of loops ?

A1: Since you have the last digit 3 in the loop, keep going in that loop
    INCLUDING the switch/if else to print the digit "three".  Group the 
    switch/if else in the loop that extracts each digit.
    Now the next loop through will give you 2  -- print "two". ...
-------------------------------------------------------------------------------

Q2: How do you reverse the order so it reads the number from left to right?

A2: This has something to do with "count", the number of iterations for
    the loop to divide 123 by ten.

For 123, count is 3.
How do you get the "1" ?  Oh divide by 100 (10*10 --> 10 to the 2 power)
How do you get the "2" ?  Oh divide by 10  (10    --> 10 to the 1 power)
How do you get the "3" ?  Oh divide by 1   (1     --> 10 to the 0 power)
Notice the pattern, how many times you must divide by 10. 

For 1234, count is 4.
How do you get the "1" ?  Oh divide by 1000 (10*10*10 --> 10 to the 3 power)
How do you get the "2" ?  Oh divide by 100  (10*10    --> 10 to the 2 power)
How do you get the "3" ?  Oh divide by 10   (10       --> 10 to the 1 power)
How do you get the "4" ?  Oh divide by 1    (1        --> 10 to the 0 power)
Think on this, hint another loop.
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