Thus pa pa is 11, ma ra is 52. Words kapa, tapa , papa, and yapa all mean the same that is 11. It was upto the author to choose one that fit the meaning of the verse well. An interesting example of this is a hymn below in the praise of God Krishna that gives the value of Pi to the 32 decimal places as .31415926535897932384626433832792.
Gopi bhaagya madhu vraata Shrngisho dadhisandhiga Khalajivita khaataava Galahaataarasandhara
The proposition "by" means the operations this sutra concerns are either multiplication or division. [ In case of addition/subtraction proposition "to" or "from" is used.] Thus this sutra is used for either multiplication or division. It turns out that it is applicable in both operations.
An interesting application of this sutra is in computing squares of numbers ending in five. Consider:
35x35 = (3x(3+1)) 25 = 12,25The latter portion is multiplied by itself (5 by 5) and the previous portion is multiplied by one more than itself (3 by 4) resulting in the answer 1225.
It can also be applied in multiplications when the last digit is not 5 but the sum of the last digits is the base (10) and the previous parts are the same. Consider:
37X33 = (3x4),7x3 = 12,21 29x21 = (2x3),9x1 = 6,09 [Antyayor dashake]
We illustrate this sutra by its application to conversion of fractions into their equivalent decimal form. Consider fraction 1/19. Using this sutra this can be converted into a decimal form in a single step. This can be done either by applying the sutra for a multiplication operation or for a division operations, thus yielding two methods.
So we start with the last digit
1Multiply this by "one more", that is, 2 (this is the "key" digit from Ekadhikena)
21Multiplying 2 by 2, followed by multiplying 4 by 2
421 => 8421Now, multiplying 8 by 2, sixteen
68421 1 <= carrymultiplying 6 by 2 is 12 plus 1 carry gives 13
368421 1 <= carryContinuing
7368421 => 47368421 => 947368421 1Now we have 9 digits of the answer. There are a total of 18 digits (=denominator-numerator) in the answer computed by complementing the lower half:
052631578 947368421Thus the result is .052631578,947368421
.0Next 10 divided by 2 is five
.05Next 5 divided by 2 is 2 with remainder 1
.052next 12 (remainder,2) divided by 2 is 6
.0526and so on.
As another example, consider 1/7, this same as 7/49 which as last digit of the denominator as 9. The previous digit is 4, by one more is 5. So we multiply (or divide) by 5, that is,
...7 => 57 => 857 => 2857 => 42857 => 142857 => .142,857 (stop after 7-1 digits) 3 2 4 1 2
This sutra is often used in special cases of multiplication.
For instance: in computing the square of 9 we go through the following steps:
The nearest power of 10 to 9 is 10. Therefore, let us take 10 as our base. Since 9 is 1 less than 10, decrease it still further to 8. This is the left side of our answer. On the right hand side put the square of the deficiency, that is 1^2. Hence the answer is 81. Similarly, 8^2 = 64, 7^2 = 49For numbers above 10, instead of looking at the deficit we look at the surplus. For example:
11^2 = 12 1^2 = 121 12^2 = (12+2) 2^2 = 144 14^2 = (14+4) 4^2 = 18 16 = 196 and so on.
This sutra applies to all cases of multiplication and is very useful in division of one large number by another large number.
This sutra complements the Nikhilam sutra which is useful in divisions by large numbers. This sutra is useful in cases where the divisor consists of small digits. This sutra can be used to derive the Horner's process of Synthetic Division.
This sutra is useful in solution of several special types of equations that can be solved visually. The word samuccaya has various meanings in different applicatins. For instance, it may mean a term which occurs as a common factor in all the terms concerned. A simple example is equation "12x + 3x = 4x + 5x". Since "x" occurs as a common factor in all the terms, therefore, x=0 is a solution. Another meaning may be that samuccaya is a product of independent terms. For instance, in (x+7)(x+9) = (x+3)(x+21), the samuccaya is 7 x 9 = 3 x 21, therefore, x = 0 is a solution. Another meaning is the sum of the denominators of two fractions having the same numerical numerator, for example: 1/(2x-1) + 1/(3x-1) = 0 means 5x - 2 = 0.
Yet another meaning is "combination" or total. This is commonly used. For instance, if the sum of the numerators and the sum of denominators are the same then that sum is zero. Therefore,
2x + 9 2x + 7 ------ = ------ 2x + 7 2x + 9 therefore, 4x + 16 = 0 or x = -4This meaning ("total") can also be applied in solving quadratic equations. The total meaning can not only imply sum but also subtraction. For instance when given N1/D1 = N2/D2, if N1+N2 = D1 + D2 (as shown earlier) then this sum is zero. Mental cross multiplication reveals that the resulting equation is quadratic (the coefficients of x^2 are different on the two sides). So, if N1 - D1 = N2 - D2 then that samuccaya is also zero. This yield the other root of a quadratic equation.
Yet interpretation of "total" is applied in multi-term RHS and LHS. For instance, consider
1 1 1 1 --- + ----- = ----- + ------ x-7 x-9 x-6 x-10Here D1 + D2 = D3 + D4 = 2 x - 16. Thus x = 8.
There are several other cases where samuccaya can be applied with great versatility. For instance "apparently cubic" or "biquadratic" equations can be easily solved as shown below:
(x-3)^3 + (x-9)^3 = 2 (x-6)^3 Note that x -3 + x - 9 = 2 (x - 6). Therefore (x - 6) = 0 or x = 6. consider (x+3)^3 x+1 -------- = -------- (x+5)^3 x + 7 Observe: N1 + D1 = N2 + D2 = 2x + 8. Therefore, x = -4.This sutra has been extended further.
This sutra is often used to solve simultaneous simple equations which may involve big numbers. But these equations in special cases can be visually solved because of a certain ratio between the coefficients. Consider the following example:
6x + 7y = 8 19x + 14y = 16 Here the ratio of coefficients of y is same as that of the constant terms. Therefore, the "other" is zero, i.e., x = 0. Hence the solution of the equations is x = 0 and y = 8/7.This sutra is easily applicable to more general cases with any number of variables. For instance
ax + by + cz = a bx + cy + az = b cx + ay + bz = c which yields x = 1, y = 0, z = 0.A corollary (upsutra) of this sutra says Sankalana-Vyavakalanaabhyam or By addition and by subtraction. It is applicable in case of simultaneous linear equations where the x- and y-coefficients are interchanged. For instance:
45x - 23y = 113 23x - 45y = 91 By addition: 68x - 68 y = 204 => 68(x-y) = 204 => x - y = 3 By subtraction: 22x + 22y = 22 => 22(x+y) = 22 => x + y = 1
It is converse of the Ekaadhika sutra. It provides for multiplications wherein the multiplier digits consist entirely of nines.
1/7 = 143x999/999999 = 142857/999999 = 0.142857 1/13 = 077x999/999999 = 076923/999999 = 0.076923 1/17 = 05882353x99999999/9999999999999999 = 0.05882352 94117647Note that
7x142857 = 999999 13x076923 = 999999 17x05882352 94117647 = 9999999999999999which says that if the last digit of the denominator is 7 or 3 then the last digit of the equivalent decimal fraction is 7 or 3 respectively.
8 -2 X 7 -3 ---------The multiplication proceeds from the most signficant digit to least significant digit (which is natural since the positional numbers are also read from MSD to LSD, thus the result can be produced "on-line"). The first digit (most significant digit) is obtained by
8 -2 \/ /\ 7 -3This process of obtaining MSD of a multiplication by cross-addition is said to be the origin of the conventional cross sign for multiplication. BTW, you can generate the following digit by multiplication and (if necessary) by forwarding the carry to more significant digits. This method (derived from Nikhilam sutra) works multiplication of multidigit numbers and numbers greater than as well as less than the base (or half the base). Consider bit more complex examples below:
97 -3 102 2 888 -112 X 98 -2 X 104 4 X997 -003 ----- ------ --------- 95,06 106,08 885,336For cases when the numbers are closer to the middle of the base, Anurupyena sutra (according to the ratio) can be used to compute deficit/excess from a ratio of the base and then ratio the result:
48 -2 (base/2 = 50) X46 -4 ------ 44,08 => 22,08
3, 2Now 2 divided by 7 will have remainder of 6 (3x2), that is
3, 2, 6Continuing
3, 2, 6, 4, 5, 1We stop when the remainder sequence starts to repeat. Now, multiply these remainders by the last digit (7) of the denominator and keep only the first digit (LSD). So we have:
7x3 = 21 => put down 1 .1 3, 2, 6, 4, 5, 1 7x2 = 14 => put down 4 .1 4 3, 2, 6, 4, 5, 1 7x6 = 42 => put down 2 .1 4 2 3, 2, 6, 4, 5, 1 Continuing .1 4 2 8 5 7 3, 2, 6, 4, 5, 1So the answer is 1/7 = .142857142857...